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تسجيل مستخدم جديدIntegral of Map into Abelian $Omega$-group
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Aleks Kleyn
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The common in ring, module and algebra is that they are Abelian group with respect to addition. This property is enough to study integration. I treat integral of measurable map into normed Abelian $Omega$-group. Theory of integration of maps into $Omega$-group has a lot of common with theory of integration of functions of real variable. However I had to change some statements, since they implicitly assume either compactness of range or total order in $Omega$-group.
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Since sum which is not necessarily commutative is defined in Omega-algebra A, then Omega-algebra A is called Omega-group. I also considered representation of Omega-group. Norm defined in Omega-group allows us to consider continuity of operations and continuity of representation.
Module is effective representation of ring in Abelian group. Linear map of module over commutative ring is morphism of corresponding representation. This definition is the main subject of the book. To consider this definition from more general poin
t of view I started the book from consideration of Cartesian product of representations. Polymorphism of representations is a map of Cartesian product of representations which is a morphism of representations with respect to each separate independent variable. Reduced morphism of representations allows us to simplify the study of morphisms of representations. However a representation has to satisfy specific requirements for existence of reduced polymomorphism of representations. It is possible that Abelian group is only $Omega$-algebra, such that representation in this algebra admits polymorphism of representations. However, today, this statement has not been proved. Multiplicative $Omega$-group is $Omega$-algebra in which product is defined. The definition of tensor product of representations of Abelian multiplicative $Omega$-group is based on properties of reduced polymorphism of representations of Abelian multiplicative $Omega$-group. Since an algebra is a module in which the product is defined, then we can use this theory to study linear map of algebra. For instance, we can study the set of linear transformations of $D$-algebra $A$ as representation of algebra $Aotimes A$ in algebra $A$.
Let $A$ be Banach algebra over commutative ring $D$. The map $f:Arightarrow A $ is called differentiable in the Gateaux sense, if $$f(x+a)-f(x)=partial f(x)circ a+o(a)$$ where the Gateaux derivative $partial f(x)$ of map $f$ is linear map of incremen
t $a$ and $o$ is such continuous map that $$ lim_{arightarrow 0}frac{|o(a)|}{|a|}=0 $$ Assuming that we defined the Gateaux derivative $partial^{n-1} f(x)$ of order $n-1$, we define $$ partial^n f(x)circ(a_1otimes...otimes a_n) =partial(partial^{n-1} f(x)circ(a_1otimes...otimes a_{n-1}))circ a_n $$ the Gateaux derivative of order $n$ of map $f$. Since the map $f(x)$ has all derivatives, then the map $f(x)$ has Taylor series expansion $$ f(x)=sum_{n=0}^{infty}(n!)^{-1}partial^n f(x_0)circ(x-x_0)^n $$
In this paper, we formulate and prove Wendroffs inequalities on time scales. Next, we deduct some of Pachpattes inequalities.
Let $A$, $B$ be Banach $D$-algebras. The map $f:Arightarrow B$ is called differentiable on the set $Usubset A$, if at every point $xin U$ the increment of map $f$ can be represented as $$f(x+dx)-f(x) =frac{d f(x)}{d x}circ dx +o(dx)$$ where $$frac{d
f(x)}{d x}:Arightarrow B$$ is linear map and $o:Arightarrow B$ is such continuous map that $$lim_{arightarrow 0}frac{|o(a)|_B}{|a|_A}=0$$ Linear map $displaystylefrac{d f(x)}{d x}$ is called derivative of map $f$. I considered differential forms in Banach Algebra. Differential form $omegainmathcal{LA}(D;Arightarrow B)$ is defined by map $g:Arightarrow Botimes B$, $omega=gcirc dx$. If the map $g$, is derivative of the map $f:Arightarrow B$, then the map $f$ is called indefinite integral of the map $g$ $$f(x)=int g(x)circ dx=intomega$$ Then, for any $A$-numbers $a$, $b$, we define definite integral by the equality $$int_a^bomega=int_{gamma}omega$$ for any path $gamma$ from $a$ to $b$.
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