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We give analytical solutions for the time-optimal synthesis of entangling gates between indirectly coupled qubits 1 and 3 in a linear spin chain of three qubits subject to an Ising Hamiltonian interaction with equal coupling $J$ plus a local magnetic field acting on the intermediate qubit. The energy available is fixed, but we relax the standard assumption of instantaneous unitary operations acting on single qubits. The time required for performing an entangling gate which is equivalent, modulo local unitary operations, to the $mathrm{CNOT}(1, 3)$ between the indirectly coupled qubits 1 and 3 is $T=sqrt{3/2} J^{-1}$, i.e. faster than a previous estimate based on a similar Hamiltonian and the assumption of local unitaries with zero time cost. Furthermore, performing a simple Walsh-Hadamard rotation in the Hlibert space of qubit 3 shows that the time-optimal synthesis of the $mathrm{CNOT}^{pm}(1, 3)$ (which acts as the identity when the control qubit 1 is in the state $ket{0}$, while if the control qubit is in the state $ket{1}$ the target qubit 3 is flipped as $ket{pm}rightarrow ket{mp}$) also requires the same time $T$.
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