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Bi-traceable graphs, the intersection of three longest paths and Hippchens conjecture

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 Added by Christian Valqui
 Publication date 2021
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and research's language is English




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Let $P,Q$ be longest paths in a simple graph. We analyze the possible connections between the components of $Pcup Qsetminus (V(P)cap V(Q))$ and introduce the notion of a bi-traceable graph. We use the results for all the possible configurations of the intersection points when $#V(P)cap V(Q)le 5$ in order to prove that if the intersection of three longest paths $P,Q,R$ is empty, then $#(V(P)cap V(Q))ge 6$. We also prove Hippchens conjecture for $kle 6$: If a graph $G$ is $k$-connected for $kle 6$, and $P$ and $Q$ are longest paths in $G$, then $#(V(P)cap V(Q))ge 6$.



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131 - Gili Golan , Songling Shan 2016
In 1966, Gallai asked whether all longest paths in a connected graph share a common vertex. Counterexamples indicate that this is not true in general. However, Gallais question is positive for certain well-known classes of connected graphs, such as split graphs, interval graphs, circular arc graphs, outerplanar graphs, and series-parallel graphs. A graph is $2K_2$-free if it does not contain two independent edges as an induced subgraph. In this paper, we show that in nonempty $2K_2$-free graphs, every vertex of maximum degree is common to all longest paths. Our result implies that all longest paths in a nonempty $2K_2$-free graph have a nonempty intersection. In particular, it gives a new proof for the result on split graphs, as split graphs are $2K_2$-free.
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