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The number of triangles is more when they have no common vertex

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 Added by Chuanqi Xiao
 Publication date 2020
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and research's language is English




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By the theorem of Mantel $[5]$ it is known that a graph with $n$ vertices and $lfloor frac{n^{2}}{4} rfloor+1$ edges must contain a triangle. A theorem of ErdH{o}s gives a strengthening: there are not only one, but at least $lfloorfrac{n}{2}rfloor$ triangles. We give a further improvement: if there is no vertex contained by all triangles then there are at least $n-2$ of them. There are some natural generalizations when $(a)$ complete graphs are considered (rather than triangles), $(b)$ the graph has $t$ extra edges (not only one) or $(c)$ it is supposed that there are no $s$ vertices such that every triangle contains one of them. We were not able to prove these generalizations, they are posed as conjectures.



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Alon and Yuster proved that the number of orientations of any $n$-vertex graph in which every $K_3$ is transitively oriented is at most $2^{lfloor n^2/4rfloor}$ for $n geq 10^4$ and conjectured that the precise lower bound on $n$ should be $n geq 8$. We confirm their conjecture and, additionally, characterize the extremal families by showing that the balanced complete bipartite graph with $n$ vertices is the only $n$-vertex graph for which there are exactly $2^{lfloor n^2/4rfloor}$ such orientations.
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187 - Chi-Fang Chen , Kohtaro Kato , 2020
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