Recently Vaughan Jones showed that the R. Thompson group $F$ encodes in a natural way all knots, and a certain subgroup $vec F$ of $F$ encodes all oriented knots. We answer several questions of Jones about $vec F$. In particular we prove that the subgroup $vec F$ is generated by $x_0x_1, x_1x_2, x_2x_3$ (where $x_i, i=0,1,2,...$ are the standard generators of $F$) and is isomorphic to $F_3$, the analog of $F$ where all slopes are powers of $3$ and break points are $3$-adic rationals. We also show that $vec F$ coincides with its commensurator. Hence the linearization of the permutational representation of $F$ on $F/vec F$ is irreducible.
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