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For an $r$-tuple $(gamma_1,ldots,gamma_r)$ of special orthogonal $dtimes d$ matrices, we say the Euclidean $(d-1)$-dimensional sphere $S^{d-1}$ is $(gamma_1,ldots,gamma_r)$-divisible if there is a subset $Asubseteq S^{d-1}$ such that its translations by the rotations $gamma_1,ldots,gamma_r$ partition the sphere. Motivated by some old open questions of Mycielski and Wagon, we investigate the version of this notion where the set $A$ has to be measurable with respect to the spherical measure. Our main result shows that measurable divisibility is impossible for a generic (in various meanings) $r$-tuple of rotations. This is in stark contrast to the recent result of Conley, Marks and Unger which implies that, for every generic $r$-tuple, divisibility is possible with parts that have the property of Baire.
Laczkovich proved that if bounded subsets $A$ and $B$ of $R^k$ have the same non-zero Lebesgue measure and the box dimension of the boundary of each set is less than $k$, then there is a partition of $A$ into finitely many parts that can be translate
We prove that any convex body in the plane can be partitioned into $m$ convex parts of equal areas and perimeters for any integer $mge 2$; this result was previously known for prime powers $m=p^k$. We also discuss possible higher-dimensional generali
Given an action of a group $Gamma$ on a measure space $Omega$, we provide a sufficient criterion under which two sets $A, Bsubseteq Omega$ are measurably equidecomposable, i.e., $A$ can be partitioned into finitely many measurable pieces which can be
We give a sketch of proof that any two (Lebesgue) measurable subsets of the unit sphere in $R^n$, for $nge 3$, with non-empty interiors and of the same measure are equidecomposable using pieces that are measurable.
Consider a polygon P and all neighboring circles (circles going through three consecutive vertices of P). We say that a neighboring circle is extremal if it is empty (no vertices of P inside) or full (no vertices of P outside). It is well known that