Purely singular splittings of cyclic groups

Let $G$ be a finite abelian group. We say that $M$ and $S$ form a textsl{splitting} of $G$ if every nonzero element $g$ of $G$ has a unique representation of the form $g=ms$ with $min M$ and $sin S$, while $0$ has no such representation. The splitting is called textit{purely singular} if for each prime divisor $p$ of $|G|$, there is at least one element of $M$ is divisible by $p$. In this paper, we mainly study the purely singular splittings of cyclic groups. We first prove that if $kge3$ is a positive integer such that $[-k+1, ,k]^*$ splits a cyclic group $mathbb{Z}_m$, then $m=2k$. Next, we have the following general result. Suppose $M=[-k_1, ,k_2]^*$ splits $mathbb{Z}_{n(k_1+k_2)+1}$ with $1leq k_1< k_2$. If $ngeq 2$, then $k_1leq n-2$ and $k_2leq 2n-5$. Applying this result, we prove that if $M=[-k_1, ,k_2]^*$ splits $mathbb{Z}_m$ purely singularly, and either $(i)$ $gcd(s, ,m)=1$ for all $sin S$ or $(ii)$ $m=2^{alpha}p^{beta}$ or $2^{alpha}p_1p_2$ with $alphageq 0$, $betageq 1$ and $p$, $p_1$, $p_2$ odd primes, then $m=k_1+k_2+1$ or $k_1=0$ and $m=k_2+1$ or $2k_2+1$.