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Grahams Number is Less Than 2^^^6

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 Added by Mikhail Lavrov
 Publication date 2013
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and research's language is English




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In [5] Graham and Rothschild consider a geometric Ramsey problem: finding the least n such that if all edges of the complete graph on the points {+1,-1}^n are 2-colored, there exist 4 coplanar points such that the 6 edges between them are monochromatic. They give an explicit upper bound: F(F(F(F(F(F(F(12))))))), where F(m) = 2^^(m)^^3, an extremely fast-growing function. By reducing the problem to a variant of the Hales-Jewett problem, we find an upper bound which is between F(4) and F(5).



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We prove that there exists an absolute constant $delta>0$ such any binary code $Csubset{0,1}^N$ tolerating $(1/2-delta)N$ adversarial deletions must satisfy $|C|le 2^{text{poly}log N}$ and thus have rate asymptotically approaching 0. This is the first constant fraction improvement over the trivial bound that codes tolerating $N/2$ adversarial deletions must have rate going to 0 asymptotically. Equivalently, we show that there exists absolute constants $A$ and $delta>0$ such that any set $Csubset{0,1}^N$ of $2^{log^A N}$ binary strings must contain two strings $c$ and $c$ whose longest common subsequence has length at least $(1/2+delta)N$. As an immediate corollary, we show that $q$-ary codes tolerating a fraction $1-(1+2delta)/q$ of adversarial deletions must also have rate approaching 0. Our techniques include string regularity arguments and a structural lemma that classifies binary strings by their oscillation patterns. Leveraging these tools, we find in any large code two strings with similar oscillation patterns, which is exploited to find a long common subsequence.
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