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Algebraic Semigroups are Strongly {pi}-regular

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 Added by Michel Brion
 Publication date 2012
  fields
and research's language is English




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Let $S$ be an algebraic semigroup (not necessarily linear) defined over a field $F$. We show that there exists a positive integer $n$ such that $x^n$ belongs to a subgroup of $S(F)$ for any $x in S(F)$. In particular, the semigroup $S(F)$ is strongly {pi}-regular.



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